Mathematical operation and symbol notation
 Statements:
N < O ≥ R > T; R < A; B ≤ T
Conclusions:
I. N < A II. B < A

 if only conclusion I is true
 if only conclusion II is true
 if either conclusion I or II is true
 if neither conclusion I nor II is true
 if both conclusion I and II are true

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N < O ≥ R > T; R < A; B ≤ T
Check for I:
N < O ≥ R > T
∴ No definite relation can be found between N and A.
Check for II:Correct Option: B
N < O ≥ R > T; R < A; B ≤ T
Check for I:
N < O ≥ R > T
∴ No definite relation can be found between N and A.
Check for II:
 Statements:
R © F, F # D, D @ M
Conclusions:
I. R © D II. M % F III. M S R

 None is true
 Only I is true
 Only II is true
 Only III is true
 Only I and II are true

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R < F ...(i) F ≥ D ...(ii) D ≤ M ...(iii)
From (i) and (ii) R and D can't be compared. Hence neight I nor III follows.
From (ii) and (iii) M and F can't be compared. Hence II does not follows.Correct Option: A
R < F ...(i) F ≥ D ...(ii) D ≤ M ...(iii)
From (i) and (ii) R and D can't be compared. Hence neight I nor III follows.
From (ii) and (iii) M and F can't be compared. Hence II does not follows.
 Statements:
M # W, W % N, N S B
Conclusions:
I. N % M II. N © M III. M S B

 Only either I or II is true
 Only either I or III is true
 Only either I or II and III are true
 Only III is true
 None of these

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M ≥ W ...(i) W = N ...(ii) N > B ...(iii)
Combining these we get M ≥ W = N > B.
Hence M ≥ N or N ≤ M,
Which means either I (N = M) or II (N < M) follows.
Also M > B and II (M ≤ D) Hence III definitely true.Correct Option: C
M ≥ W ...(i) W = N ...(ii) N > B ...(iii)
Combining these we get M ≥ W = N > B.
Hence M ≥ N or N ≤ M,
Which means either I (N = M) or II (N < M) follows.
Also M > B and II (M ≤ D) Hence III definitely true.
 Statements:
M # W, W % N, N S B
Conclusions:
I. N % M II. N © M III. M S B

 Only either I or II is true
 Only either I or III is true
 Only either I or II and III are true
 Only III is true
 None of these

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M ≥ W ...(i) W = N ...(ii) N > B ...(iii)
Combining these we get M ≥ W = N > B.
Hence M ≥ N or N ≤ M,
Which means either I (N = M) or II (N < M) follows.
Also M > B and II (M ≤ D) Hence III deficitely true.Correct Option: C
M ≥ W ...(i) W = N ...(ii) N > B ...(iii)
Combining these we get M ≥ W = N > B.
Hence M ≥ N or N ≤ M,
Which means either I (N = M) or II (N < M) follows.
Also M > B and II (M ≤ D) Hence III deficitely true.
 Statements:
W @ F, F S M, M © D
Conclusions:
I. D S F II. W © B III. F S D

 None is true
 Only I is true
 Only II is true
 Only III is true
 Only II and III are true

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W ≥ F ...(i) F > M ...(ii) M < D ...(iii)
From (i) and (ii) W and M can't be compared. Hence II does not follow.
From (ii) and (iii) F and D can't be compared. Hence neither I or III follows.Correct Option: A
W ≥ F ...(i) F > M ...(ii) M < D ...(iii)
From (i) and (ii) W and M can't be compared. Hence II does not follow.
From (ii) and (iii) F and D can't be compared. Hence neither I or III follows.